`10` ml of `H_(2)O_(2)` liberates `12.7 g` of iodine from an acidic `KI` solution. Calculate (a) normality, (b) molarity, (c) volume strength. (d) Strength and (c) percentage strength of `H_(2)O_(2)`.

Explanation

a `MW(I_(2))=2xx127=254 g`
`EW(I_(2))=254/2=127 g`
`( :' 2I^(ɵ) to I_(2)+2e^(ɵ),n=2)`
`H_(2)O_(2)=KI-=I_(2)`
`N_(1)V_(1)(mL)=("Weight of" I_(2))/(EWI_(2))xx10^(3)(mEq)`
`N_(1)xx10 mL=(12.7xx10^(3))/127`
`N_(1)`of `H_(2)O_(2)-=10N`
(b). Molarity of `H_(2)O_(2)=N/("n-factor")=10/2=5M`
(c) `1N of H_(2)O_(2)=5.6` volume strength of `H_(2)O_(2)`
`10 N of H_(2)O_(2)=5.6xx10=56` volume strength of `H_(2)O_(2)`
(d) `1Nof H_(2)O_(2)=17 gL^(-1)`
`10 Nof H_(2)O_(2)=17xx10=170 gL^(-1)`
(e) `1N of H_(2)O_(2) =1.7 %`
`10 N of H_(2)O_(2)=17%`