When `100 mL` of an aqueous of `H_(2)O_(2)` is titrated with an excess of `KI` solution in dilute `H_(2)O_(2)`, the liberated `I_(2)` required `50 mL` of `0.1 M Na_(2) S_(2)O_(3)` solution for complete reaction. Calculate the percentage strength and volume strength of `H_(2)O_(2)` solution.

Explanation

To solve the problem, we need to follow these steps:

### Step 1: Determine the moles of Na2S2O3 used
We know that the volume of Na2S2O3 solution used is 50 mL and its concentration is 0.1 M.

Using the formula for moles:
\[
\text{Moles of Na2S2O3} = \text{Concentration (M)} \times \text{Volume (L)}
...