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200 mL of acidified 3 N H(2)O(2) is reac...

`200 mL` of acidified `3 N H_(2)O_(2)` is reacted with `KMnO_(4)` solution till there is a light tinge of purple colour. Calculated the volume of `O_(2)` produced at `STP`.

Text Solution

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`N of H_(2)O_(2)=5.6` volume of `O_(2)`
`3N of H_(2)O_(2)=3xx5.6=16.8` volume of `O_(2)` (volume stregth of `H_(2)O_(2)`)
Volume of `O_(2)` produced by `H_(2)O_(2) at STP`
=Volume of `O_(2)xx`Volume strength of `H_(2)O_(2)`
`=200mLxx16.8=3360 mL`
Same volume will be produced by `KMnO_(4)=3360 mL`
Total volume of `O_(2)` produced `=3360+3360=6720=6.72 L`
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