Home
Class 11
CHEMISTRY
To a 25 mL H(2)O(2) solution excess of a...

To a 25 mL `H_(2)O_(2)` solution excess of an acidified solution of potassium iodide was added. The iodine liberated required 20 " mL of " 0.3 N sodium thiosulphate solution Calculate the volume strength of `H_(2)O_(2)` solution.

Text Solution

Verified by Experts

`mEq of Na_(2)S_(2)O_(3)=20xx0.3=6`
`mEq of I_(2)=6`
`mEq of H_(2)O_(2)=6`
Normality of `H_(2)O_(2)=6/25`
For `H_(2)O_(2)`
`5.6xx` Normality=Volume strength
`:.` Volume strength `=5.6xx6/25=1.344`
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Ex 3.1|4 Videos

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Ex 3.2|36 Videos

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Subjective Archive (Subjective)|3 Videos

  • GENERAL ORGANIC CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Analytical and Descriptive|1 Videos

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Archives Subjective|28 Videos

Similar Questions

Explore conceptually related problems

25 mL of H_(2)O_(2) solution were added to excess of acidified solution of KI . The iodine so liberated required 20 mL of 0.1N Na_(2)S_(2)O_(3) for titration Calculate the strength of H_(2)O_(2) in terms of normalility, percentage and volumes. (b) To a 25 mL H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3N sodium thiosulphate solution. Calculate the volume strength of H_(2)O_(2) solution.

To a 25 mL of H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3 N Na_(2)S_(2)O_(3) solution. Calculate the volume strength of H_(2)O_2 solution. Strategy : Volume strength of H_(2)O_(2) solution is related to its normality by the following relation Volume strength (V)=5.6xx"Normality" (N) where, Normality =((meq)H_(2)O_(2))/V_(mL) According to the law of equivalence (meq)_(Na_(2)S_(2)O_(3))=(meq)_(I_(2))=(meq)_(H_(2)O_(2))

To a 25 mL H_2 O_2 solution, excess of acidified solution of KI was added. The iodine liberated required 20.0 mL of 0.3 N Na_2 S_2 O_3 solution. Calculate the volume strength of H_2 O_2 solution.