Home
Class 11
CHEMISTRY
Calculate the volume of 10 volume H(2)O(...

Calculate the volume of `10` volume `H_(2)O_(2)` solution that will react with `200 mL of 2N KMnO_(4)` in acidic medium.

Text Solution

Verified by Experts

Normality of `10` volume `H_(2)O_(2)=("Volume strength")/5.6=10/5.6 N`
Applying normality equation,
`N_(1)V_(1)=N_(2)V_(2)`
`(H_(2)O_(2))=(KMnO_(4))`
`10/5.6xxV_(1)=2xx200`
`V_(1)=(2xx200xx5.6)/10=224 mL`
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Ex 3.1|4 Videos

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Ex 3.2|36 Videos

  • HYDROGEN, WATER AND HYDROGEN PEROXIDE

    CENGAGE CHEMISTRY|Exercise Subjective Archive (Subjective)|3 Videos

  • GENERAL ORGANIC CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Analytical and Descriptive|1 Videos

  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Archives Subjective|28 Videos

Similar Questions

Explore conceptually related problems

The volume of 10 volume H_(2)O_(2) solution that decolourises 200 mL of 2 N KMnO_(4) solution in acidic medium is

Calculate the volume of 10 volume H_2 O_2 required to neutralise 200 mL of 2N KMnO_4 in acidic medium.

What volume of 0.1M H_(2)O_(2) solution will be required to completely reduce 1 litre of 0.1 M KMnO_(4) in acidic medium?