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If 100 mL of acidified 2NH(2)O(2) is all...

If `100 mL` of acidified `2NH_(2)O_(2)` is allowed to react with `KMnO_(4)` solution till there is light tinge of purples colour, the volume of oxygen produced at `STP` is :

A

`2.24 L`

B

`1.12 L`

C

`3.36 L`

D

`4.48 L`

Text Solution

Verified by Experts

The correct Answer is:
A
Volume of `O_(2)` at `STP=100 mLxx11.2` volume strength `=1120 mL of O_(2) at STP`
(Since `1N=5.6` volume strength `2N=11.2` volume strength of `H_(2)O_(2)`)
volume of `O_(2)` produced by `H_(2)O_(2)=1120 mL`
Same volume of `O_(2)` produced by `KMnO_(4)=1120 mL`
Total volume of `O_(2)=2240 mL=2.24 L`
Hence, the correct options (a).
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