Hydrogen peroxide in its reaction with `KIO_(4)` and `NH_(2)OH` respectively, is acting as a

Options

A. reducing agent,oxidising agent
B. reducing agent, reducing agent
C. oxidising agent,oxidising agent
D. oxidising agent, reducing agent

Answer

A

Explanation

`H_(2)O_(2)` reacts with `KIO_(4)` in the following mannter:
`overset(+7)(KIO_(4))+H_(2)O_(2)tooverset(+5)(KIO_(3))+H_(2)O+O_(2)`
On reaction of `KIO_(4)` with `H_(2)O_(2)`, oxidation state of `I` varies from `+7` to `+5` i.e, decreases. Thus `KIO_(4)` get reduced hence, `H_(2O_(2)` reacts with `NH_(2)OH` in the following manner:
`overset(-1)(N)H_(2)OH+H_(2)O_(2)to overset(+3)(N_(2))O_(3)+H_(2)O`
In this reaction,oxdation state of `N` varies from `-1` to `+3` ie., increases, hence `H_(2)O_(2)` is acting on an oxidation agent here.