The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` are

Options

A. `0 and -1`
B. `-1 and -2`
C. `-2 and 0`
D. `-2 and +1`

Answer

B

Explanation

`BaO_(2)+H_(2)SO_(4)rarrBaSO_(4)+H_(2)O_(2)`
In `BaSO_(4)`, oxidation state of `O^(2-)` is `-2`.
In `H_(2)O_(2)`, oxidation state of oxygen is `-1`.