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Boric acid can be titrated against sodiu...

Boric acid can be titrated against sodium hydroxide using phenolphthalein as an indicator only in the presence of polyhydroxy compounds like glycol. Glycerol etc. Give reason.

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Boric acid can be titrated against sodium hydroxide using methyl orange as indicator only in the presence of polyhydroxy compounds wlike catechol, manniton etc. explain.

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Assertion: In the titration of Na_(2)CO_(3) with HCl using methyl orange indicator, the volume of acid required is twice that of the acid required using phenolphthalein as indicaton. Reason: Two moles of HCl are required for the complete neutralisation of one mole of Na_(2)CO_(3) .

CENGAGE CHEMISTRY-P-BLOCK GROUP 13 - BORON FAMILY-Ex 6.1 (Subjective)
  1. Why boron does not exist as B^(2+) ion in solution or in compound ?

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  2. The +1 oxidation state is more stable than +3 oxidation state for thal...

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  3. Aluminium chloride exists as dimer. Give reason.

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  4. Why boron halides do not exists as a dimer. While AlCl(3) exists as Al...

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  5. Give reaction for the following : (a) In (III) is more stable than i...

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  6. Why boron and aluminium tend to for, covalent compounds ?

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  7. Molten aluminium bromide is a poor conductor of electricity. Give reas...

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  8. Why B-X bond distance in BX(3) is shorter than theoretically expected ...

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  9. Boric acid can be titrated against sodium hydroxide using phenolphthal...

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  10. Which one is more soluble in diethyl ether : anhydrous AlCl(3) or hydr...

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  11. How is boron obtained from borax ? Give the chemical reactions involve...

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  12. Unlike ordinary fire, thermite reaction cannot be stopped by pouring w...

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  13. (a) Explain why BF(3) exists whereas BH(3) does not. (b) Compare the...

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  14. State with equations what happens when borax is heated on a platinum w...

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  15. What is inorganic benzene ? Why is it so called ? How will you get it ...

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  16. AlF(3) is insoluble in anhydrous HF but dissolves on addition of NaF. ...

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  17. What do you understand by : (a) Ammonal (b) Bentonite ( c) Rubie...

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