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Energy of an electron in the ground stat...

Energy of an electron in the ground state of the hydrogen atom is `-2.18xx10^(-18)J`. Callate the ionisation enthalpy of atomic hydrogen in terms of `kJ mol^(-1)`.
Hint: Apply the idea of mole concept to derive the answer.

Text Solution

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The energy required to remove an electron in the ground state of hydrogen atom
=-(its energy in the ground state)=-`(-2.18xx10^(-18))`
`2.18xx10^(-18)`
`:.` IE per mol of hydrogen atoms
`=(2.18xx10^(-18)xx6.02xx10^(23))/(1000)kJ`
`=13.12.36 kJ "mol"^(-1)`
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