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One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals (1) 1/14                                                (2) 1/7 (3) 5/14                                                (4) 1/50

Text Solution

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set A= `{ 8,17, 26, 35,44}`
set B= `{00,01,.......09,10,20,30,40}`
`P(A/B)= (P(A nn B))/(P(B))`
`= (1/50)/(14/50)`
`= 1/14`
option 1 is correct
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