इन समाकलनो का मान कीजिएः
`int_(0)^(pi//4) sin3x sin 2xdx`

Explanation

`underset(0)overset(pi//4)int sin3x sin 2dx`
`=1/2underset(0)overset(pi//4)int (2 sin 3 x sin2x)dx`
`=1/2underset(0)overset(pi//4)int (cos x-cos 5x)dx` `[therefore 2 sin A sin B=cos (A-B)-cos(A+B)]`
`=1/2[sin x-(sin 5x)/(5)]_(0)^(pi//4)`
`=1/2[1/sqrt2+1/5sin""(pi)/(4)]=1/2[1/sqrt2+1/(2sqrt2)]`
`=(6)/(2(5sqrt2))=(3sqrt2)/(10)`