मूल्यांकन कीजिएः
`int_(0)^(pi) sin^(3)xdx`

Explanation

`underset(0)overset(pi)int sin^(3)xdx`
`underset(0)overset(pi)int (3sin x-sin 3x)/(4)dx, [therefore sin 3x=3sin x-4sin^(3)x]`
`=1/4underset(0)oversetpiint (3 sin x- sin 3x)dx`
`=1/4[-3 cosx+(cos 3x)/(3)]_(0)^(pi)`
`=1/4[{-3 cos pi+(cos 3x)/(3)} -{-3 cos 0+(cos 0)/(3)}`
`=1/4[{-3xx(-1)+((-1))/(3)}-{-3+1/3}]`
`=1/4[(3-1/3)-(-3+1/3)]`
`=1/4 (6-2/3)=1/4xx16/3=4/3`