संमाकलनो का मान ज्ञात कीजिएः।
`int_(4)^(9) (sqrtx)/((30-x^(3//2))^(2))d x`

Explanation

यहाँ `underset(4)overset(9)int (sqrtx)/((3-x^(3//2))^(2))dx`
माना `30-x^(3//2)=t rArr -3/2sqrtx dx=dt`
और `x=9 rArr 30=(9)^(3//2)=39-27=3`
`therefore I=2/3 underset(22)overset(3)int =-2/3underset(22)overset(3)int t^(-2)dt`
`=-2/3.[(-1)/(t)]_(22)^(3)=-2/3[-1/3+1/22]`
`=-2/3 xx (-19)/(66)=(19)/99`