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Find the value of 0.3258....

Find the value of `0.3258.`

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Let `R=0.3258`
`implies R= 0.32585858585"....." " " "......(i)"`
Here, number of figures which are not recurring is 2 and number of figures which are recurring is also 2.
Then, `100R= 32.585858585"....." " " "......(ii)"`
and `10000R= 3258.585858585"....." " " "......(iii)"`
On subtracting Eq.(ii) from Eq.(iii), we get
`9900R= 3226`
`therefore " " R= (3226)/(9900)`
Hence, `" " R= (1613)/(4950)`
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ARIHANT MATHS-SEQUENCES AND SERIES-Exercise (Questions Asked In Previous 13 Years Exam)
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