If the continued product of three numbers in GP is 216 and the sum of their products in pairs is 156, then find the sum of three numbers.

Explanation

To solve the problem, we need to find three numbers in a geometric progression (GP) given two conditions: the continued product of the numbers is 216, and the sum of their products in pairs is 156.

Let's denote the three numbers in GP as:
- \( a/r \)
- \( a \)
- \( ar \)

### Step 1: Set up the equations based on the problem statement.
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