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Let matrix A=[(4,6,6),(1,3,2),(-1,-4,-3)...

Let matrix `A=[(4,6,6),(1,3,2),(-1,-4,-3)],` Find the non-zero column vector X such that `AX= lambdaX` for some scalar `lambda.`

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To solve the problem, we need to find a non-zero column vector \( X \) such that \( AX = \lambda X \) for some scalar \( \lambda \). This is equivalent to finding the eigenvalues and eigenvectors of the matrix \( A \). ### Step 1: Set up the equation We start with the equation: \[ AX = \lambda X \] which can be rewritten as: ...
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