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If P is a non-singular matrix, with (P^-...

If P is a non-singular matrix, with `(P^-1)` in terms of `'P',` then show that `adj (Q^(-1) BP^-1) = PAQ` . Given that `adjB = A and abs(P) = abs(Q) = 1.`

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`because adj (P^-1) = abs(P) (P^-1) ^(-1) = abs(P ) P = P " "[because abs(P)= 1]`
and `adj (Q^(-1) BP^(-1))=adj (P^-1)cdotadjBcdotadj(Q^(-1))`
`=P/abs(P) A cdot Q/abs(Q) = PAQ" " [because abs(P) = abs(Q) =1]`
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