Plot `y=e^(x),y=e^(x)+1 and y=e^(x)-1.`

The area of the region bonded by y=e^(x),y=e^(-x),x=0 and x = 1 is

What is the area bounded by the curves y=e^(x),y=e^(-x) and the straight line x=1?

What is the area bounded by the curves y=e^(x),y=e^(-x) and the straight line x=1?

if y=(e^(x))/(1+e^(x)) find (dy)/(dx)

The equation of one of the curves whose slope of tangent at any point is equal to y+2x is (A) y=2(e^(x)+x-1) (B) y=2(e^(x)-x-1) (C) y=2(e^(x)-x+1) (D) y=2(e^(x)+x+1)

if y=log(e^(2x)+sqrt(1+e^(4x))) and y_(1)sqrt(1+e^(4x))=me^(mx) then m=

If A={(x,y):y=e^(x),x in R} and B={(x,y):y=e^(-2x),x in R}, then

Let A={(x,y):y=e^(x) , x in R } B={(x,y),Y=e^(-x) ,x in R} then