Plot `y=sin(x+(pi)/(4)) and y =sin(x-(pi)/(4))`.

The equation of tangent to the curve y=sqrt(2) sin (2x+(pi)/(4))" at "x=(pi)/(4) is

The equation of normal to the curve y=sqrt(2) sin (2x+(pi)/(4))" at "x=(pi)/(4) is

Prove the following cos ((pi) / (4) -x) cos ((pi) / (4) -y) -sin ((pi) / (4) -x) sin ((pi) / (4) - y) = sin (x + y)

Prove that (i) cos (n + 2) x cos (n+1) x +sin (n+2) x sin (n+1) x = cos x) (ii) " cos " .((pi)/(4)-x) " cos " .((pi)/(4)-y) " - sin " ((pi)/(4)-x ) " sin " ((pi)/(4) -y) =" sin " (x+y)

Statement -1 The value of determinant |{:(sinpi,cos(x+(pi)/(4)),tan(-(pi)/(4))),(sin(x-(pi)/(4)),-cos((pi)/(2)),In((x)/(y))),(cot((pi)/(4)+x),In((y)/(x)),tan(pi)):}| is zero Statement -2 The value of skew -symetric determinat of odd order equals zero.

prove that sin((pi)/(4)+x)+sin((pi)/(4)-x)=sqrt(2)cos x

Plot y = sin x and y = 2sin x

Prove that: cos((pi)/(4)-x)cos((pi)/(4)-y)-sin((pi)/(4)-x)sin((pi)/(4)-y)=sin(x+y)

If x=sin((pi)/(3)+A)*cos((pi)/(3)+B) and y=cos((pi)/(3)+A)*sin ((pi)/(3)+B) then x-y=

Number of intersection points of the curves y=sin^(-1)((2x)/(1+x^(2))) and |y|=(pi)/(4) is