Home
Class 12
MATHS
The number of real solution of the equat...

The number of real solution of the equation `sqrt(1 + cos 2x) = sqrt2 sin^(-1) (sin x), -pi le x le pi`, is

Text Solution

Verified by Experts

The correct Answer is:
`x = (pi)/(4), (-3pi)/(4)`
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC EQUATIONS AND INEQUATIONS

    ARIHANT MATHS|Exercise Exercise For Session 1|15 Videos

  • TRIGONOMETRIC EQUATIONS AND INEQUATIONS

    ARIHANT MATHS|Exercise Exercise For Session 2|8 Videos

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|44 Videos

  • TRIGONOMETRIC FUNCTIONS AND IDENTITIES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|19 Videos

Similar Questions

Explore conceptually related problems

The number of real solutions of equation sqrt(1+cos2x)=sqrt(2)sin^(-1)(sinx),-10pilexle10pi is/are

The number of real solutions of the equation sqrt(1+cos2x)=sqrt(2)sin^(-1)(sin x),-pi<=x<=pi is 0(b)1(c)2(d) infinite

The number of real solutions of the equation sqrt(1+cos2x) = sqrt(2)cos^(-1)(cosx) in [pi/2,pi] is

The solution of the equation "cos"^(2) x-2 "cos" x = 4 "sin" x - "sin" 2x (0 le x le pi) , is

Find the number of solution of the equation sqrt(cos 2x+2)=(sin x + cos x) in [0, pi] .

The number of solutions of the equation |2 sin x-sqrt(3)|^(2 cos^(2) x-3 cos x+1)=1 in [0, pi] is

Number of solutions of the equation sin x + cos x-2sqrt(2) sin x cos x=0 for x in [0, pi] is