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The reaction of white phosphorous with a...

The reaction of white phosphorous with aqueous `NaOH` gives phosphine along with another phosphorous containing compound. The reason type , the oxidation state of phosphorous in phosphine and in the other products are, respectively,

A

redox reaction , `- 3 and - 5`

B

redox reaction , `+3 and + 5`

C

disproportionation reaction , ` - 3 and + 5`

D

Disproportionation reaction , ` - 3 and + 3`.

Text Solution

Verified by Experts

The correct Answer is:
C
`P_4 (s) + NaOH rarr overset (-3) (PH_3) + NaH_2 overset (+1) (PO_2) (aq) overset (Delta) rarr Na_3 overset (+5) (PO_4) + overset (-3) (PH_3)`
Oxidation state of `P` in `PH_3` and `Na_3 PO_4` are `-3` and `+ 5` respectively. It is a disproportionation reaction.
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The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reacation type, the oxidation states of phosphorus in phosphine and the other product are respectvely:

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