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The oxidation states of the most electro...

The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` with dilute `H_2SO_4` are

A

`0` and `-1`

B

`-1` and `-2`

C

`-2` and `0`

D

`-2` and `-1`

Text Solution

Verified by Experts

The correct Answer is:
D
`BaO_(2) + H_(2) SO_(4) rarr BaSO_(4) + H_(2) O`
The oxidation state of `O` in `BaSo_(4)` is `- 2`.
The oxidation state of `O` in `H_(2) O_(2)` is `- 1`.
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