Two elements A and B are such that Bond energy of A-A,B-B `&` A-B are respectively 81 Kcal/mol, 64 Kcal/mol and 88 Kcal/mol. If electronegativity of B is 3 then electronegativity of A may be

What is the bond enthalpy of Xe-F bond if Ionization energy of Xe = 279 kcal/mol B.E.(F-F) = 38 kcal/mol, electron affinity of F = 85 kcal//mol

If the ionisation energy and electron affinity of an element are 275 and 86 Kcals "mol"^(-1) respectively, the electronegativity of that element on Mulliken scale is

The ionisation potentials of atoms A and B are 400 and 300 kcal mol^(-1) respectively. The electron gain enthalpy of these atoms are 80.0 and 85.0 kcal mol^(-1) respectively. Which of the atoms has highrt electronegativity.

The ionisation potentials of atoms A and B are 400 and 300 kcal mol^(-1) respectively. The electron gain enthalpy of these atoms are 80.0 and 85.0 kcal mol^(-1) respectively. Which of the atoms has highrt electronegativity.

For a diatomic molecule AB, the electronegativity difference between A and B= 0.2028 sqrt triangle where triangle =[Bond energy of AB- Geometric mean of the bond energies of A_2 and B_2]. The electonegativities of fluorine and chlorine are 4.0 and 3.0 respectively and the bond energies are of F-F : 38 kcal mol^-1 and Cl-Cl : 58 kcal mol^-1 . The bond energy of Cl-F is:

If the ionisation enthalpy and electron gain enthalpy of an element are 275 and 86 kcal mol^(-1) respectively, then the electronegativity of the element on the pauling scale is: