The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.
R, S and T, respectively, are

Options

A. `SO_(2)CI_(2)`, `PCI_(5)` and `H_(3)PO_(4)`
B. `SO_(2)CI_(2)`, `PCI_(3)` and `H_(3)PO_(3)`
C. `SOCI_(2)`, `PCI_(3)` and `H_(3)PO_(2)`
D. `SOCI_(2)`, `PCI_(5)` and `H_(3)PO_(4)`

Answer

A

Explanation

`SO_(2)+CI_(2)overset(Charcoal)rarr underset(R )SO_(2)CI_(2)`
`SO_(2)CI_(2)P_(4)rarr PCI_(5)+SO_(2)`
`PCI_(5)+H_(2)O rarr underset(T)H_(3)PO_(4) +HCI`