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Noble gases have compleately filled vala...

Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`,
`XeF_(4)` and `XeF_(4)` are expected to be

A

oxidising

B

reducing

C

unreactive

D

strongly basic

Text Solution

Verified by Experts

The correct Answer is:
a
`XeF_(4)` and `xeF_(4)` are expected to be oxidising in such reactions, the oxidation state xenone decreased
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