What will be the correct representation of quatum numbers f the last electron entered into Ce?

Options

A. `n=1,l=3,m=-3,s=(-1)/(2)`
B. `n=4,l=3,m=0,s=(-1)/(2)`
C. `n=4,l=2,m=-3,s(+1)/(2)`
D. `n=4,l=3,m=+2,s=(-1)/(2)`

Answer

a,b,d

Explanation

`Ce(Z=58)` f-block element: Last electron enters in f-orbital and highest value of `n=6` but the last electron will enter in 4f-orbitals filled would be `[Xe]6s^24f^15d^1`