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Number of moles of K2Cr2O7 reduced by on...

Number of moles of `K_2Cr_2O_7` reduced by one mole of `Sn^(2+)` ion is

A

`(1)/(3)`

B

`3`

C

`(1)/(6)`

D

6

Text Solution

Verified by Experts

The correct Answer is:
a

Eq. of `Cr_2O_7^(2-)=`Eq. of `Sn^(2+)`
(`n` factor`=6`) (`n` factor`=6`) ltbr `(1)/(6)` mol. Of `Cr_2O_7^(2-)=(1)/(2)`mol. Of `Sn^(2+)`
1 mol of `Sn^(2+)=(2)/(6)=(1)/(3)` mol. Of `Cr_2O_7^(2-)`
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