If common chord of cicles `x^(2)+y^(2)+5kx+2y+k=0` and `x^(2)+y^(2)+kx+(y)/(2)+(1)/(2)=0` is `4x-5y-k=0`
then number of values of `k` is

Two circles x^(2) + y^(2) -2kx = 0 and x^(2) + y^(2) - 4x + 8y + 16 = 0 touch each other externally.Then k is

The angle between the circles x^(2)+y^(2)-12x-6y+41=0 and x^(2)+y^(2)+kx+6y-59=0 is (pi)/(4) then k=

The angle between the circles x^(2)+y^(2)-12x-6y+41=0 and x^(2)+y^(2)+kx+6y-59=0 is (pi)/(4) then k=

The angle between the circles x^(2)+y^(2)-12x-6y+41=0 and x^(2)+y^(2)+kx+6y-59=0 is (pi)/(4) then k=

If the circles x^(2) + y^(2) + 5 Kx + 2y + K = 0 and 2x^(2) + y^(2)) + 2Kx + 3y - 1 = 0, (K in R) intersect at the point P and Q then the line 4x + 5y - K = 0 passes P and Q for :

The value of k so that x^(2)+y^(2)+kx + 4y+ 2=0 and 2(x^(2) + y^(2)) - 4x - 3y + k = 0 cut orthogonally is

The value of k, if the circles 2x ^(2) + 2y ^(2) - 4x + 6y = 3 and x ^(2) + y ^(2) + kx + y =0 cut orthogonally is