The spin only magnetic moment value of `[MnBr_(4)]^(2-)` ion is `5.9BM` On the basis of `VBT` Predict the hybridisation and geometry of `[MnBr_(4)]^(2-)` ion ` .

Explanation

To solve the question regarding the hybridization and geometry of the ion \([MnBr_4]^{2-}\) based on its spin-only magnetic moment value of \(5.9 \, BM\), we can follow these steps:

### Step 1: Determine the oxidation state of manganese in \([MnBr_4]^{2-}\)
The bromide ion (\(Br^-\)) has a charge of \(-1\). Since there are four bromide ions, their total contribution to the charge is \(-4\). The overall charge of the complex ion is \(-2\). Therefore, we can set up the equation:

\[ x + 4(-1) = -2 \]
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