Predict the number of unpaired electrons in square planar `[PtCI_(4)]^(2-)` ion .

Explanation

Oxidation state of Pt in `[PtCI_(4)]^(2-)` hybridisation is required For the avilabitity of one d-orbitals Hence there should be no unpaired electrons `[PtCI_(4)]^(2-)` ion

Since `CI^(Θ)` being weak ligand so pairing of `3d` electrons should not occur but for square planar complex `(dsp^(2))` hybridisation pairing of electrons in `2` half-filed `5d` orbitals occurs .