Prove that the lowering of the stabilised orbitals is `0.4Delta_(0)` while raising of the destabilised orbitalsw is `0.6Delta_(0)` .

Explanation

The total energy of separation is `Delta_(0)` Let `x=` energy of stabilisation and `y=` energy of destabilisation Then `y-x=Delta_(0)` Since the orbitals yield no net increase in energy when they are equally occupied
`3x +2y =0`
`implies 3x +2 (Delta_(0)) =0`
`:. 5x = -2Delta_(0) x = - 0.4 Delta_(0)` and `y = +0.6 Delta_(0)` .