Determine the crystal field stabilisation energy of a `d^(6)` complex having `Delta_(0) = 25000cm^(-1)` and ` P =1500cm^(-1)` .

Explanation

To determine the crystal field stabilization energy (CFSE) of a \(d^6\) complex with given parameters, we can follow these steps:

### Step 1: Identify the given values
- Crystal field splitting energy (\(\Delta_0\)) = 25,000 cm\(^{-1}\)
- Pairing energy (P) = 1,500 cm\(^{-1}\)

### Step 2: Determine the electron configuration for \(d^6\)
Since \(\Delta_0 > P\), electrons will pair up in the lower energy \(t_{2g}\) orbitals before occupying the higher energy \(e_g\) orbitals. For a \(d^6\) configuration:
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