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Crystal field splitting energy (CFSE) fo...

Crystal field splitting energy `(CFSE)` for the complex `[Cr(NH_(3))_(6)]^(2+)` is (when `Delta gtP`) .

A

`-1.6Delta_(0)+P`

B

`1.6Delta_(0)+P`

C

`-c-24Delta_(0) +P`

D

`2.4Delta_(0)+P`

Text Solution

Verified by Experts

The correct Answer is:
a
Octahedral complex `CN =6 DeltagtP`
`("Strong ligand no Pairing low spin state")`
`Cr =3d^(5) 4s^(1),`Cr^(+2) = 3d^(4)` Structure is `3(t_(2g)^(2)e_(g)^(1))`
CFSE = `(-0.4 xx 4)Delta_(0) + P = -1.6 Delta_(0) + P` .
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Corystal field splitting energy (CFSE) for the complex [Cr(H_(2)O)_(6)]^(2+) is when (DeltaltP) .

Crystal field splitting energy (CFSE) for the complex [Cr(NH_(3))_(6)]^(2+) is when P =125 and Delta_(0) =250kjmol^(-1) .

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Crystal field splitting energy (CFSE) for the complex [Cr(H_(2)O)_(6)]^(2+) is when P =20925cm^(-1) and Delta_(0) = 10462.5cm^(-1)(1kJmo1^(-1) = 83.7 cm^(-1)) .

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Define crystal field splitting energy ?

In which structure crystal field splitting energey (CFSE) for octahedral complex will be zero when DeltaltP .

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