The total number of possibel coordination isomer for the given compounds `[Pt(NH_(3))(4)Br_(2)][PtBr_(4)]` is .

Options

A. `2`
B. `4`
C. `5`
D. `3`

Answer

B

Explanation

`[Pt^(4+)CI_(2)(NH_(3))_(4)]^(2+)[Pt^(2+)CI_(4)]^(2-)`
(2) `[Pt^(4+)CI_(3)(NH_(3)]^(o+)[Pt^^(2+)CI_(3)(NH_(3))]^(o+)`
(3) `[Pt^(2+)CI(NH_(3))_(3)]^(o+)[Pt^(4+)CI_(5)(NH_(3))]^(Θ)`
(4) `[Pt^(2+)(NH_(3))_(4)]^(2+)[Pt^(4+)CI_(6)]^(2-)` .