Draw the structures of `[Co(NH_(3))_(6)]^(3+),[Ni(CN)_(4)]^(2-)` and `[Ni(CO)_(4)]` Write the hybridisation of atomic orbitals of the transition metal in each case .

Explanation

`[Co(NH_(3))_(6)]?^(3+)`
The oxidation number of `Co` is +3 Atomic number `=27`
`Co = [Ar]3d^(7) 4s^(2)`
`Co=[Ar]3d^(6) 4s^(0)`
In this case `NH_(3)` cause pairing
`d^(2) sp^(3)` hubridisation (octahedral) There are no unpaired electrons, so the complex is diamagnetic Spin magnetic moment = zero
(ii) `[Ni(CN)_(4)]^(2-)`
The oxidation nuber of `Ni is +2`
Atomic number `=28`
`Ni=[Ar]3d^(8) 4s^(2)`
`Ni^(2+) =[Ar]3d^(8)`
Cyano is a strong filed ligand it causes pairing
`dsp^(2)`-hybrisation (square planar) There are no unpaired electrons so the complex is diamgentic Spin magnetic magnetic moment =zero
(iii) `[Ni(CO)_(4)]`
THe oxidation number of Ni is 0 Atomic number `=28`
`Ni =[Ar] 3d^(8) 4s^(2)`
`CO` is a strong field ligand it cause pairing
`sp^(3)` hybridisation (tetrahedral) There are no unpaired electrons, so the complex is diamagnetic Spin magnetic moment = zero .