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How would you account for the following....

How would you account for the following.
(i). Of the `d^4` species. `Cr^(2+)` is strongly reducing while manganese (III) is strongly oxidising.
(ii). Cobalt (II) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidised.
(iii). The `d^1` configuration is very unstable in ions.

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(i). `E^(ɵ)` value for `((Cr^(3+))/(Cr^(2+)))` is negative `(-0.41V)` whereas `E^(ɵ)` value for `((Mn^(3+))/(Mn^(2+)))` is positive `(+1.57V)`. Hence `Cr^(2+)` ions can easily undergo oxidation to give `Cr^(3+)` ions and therefore, act as strong reducing agent whereas `Mn^(2+)` can easily undergo reduction to give `Mn^(2+)` and hence act as oxidising agent.
(ii). `Co^(3+)` has greater tendecny to form coordination complexes than `Co^(2+)`. Hence in the presence of ligands `Co^(2+)` changes to `Co^(3+)` i.e., is easily oxidised.
(iii) The ions with `d^1` configuration have the tendency to lose the only electron present in d-subshell to acquire stable `d^0` configuration. Hence, they are unstable and undergo oxidation or disproportionation.
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How would you account for the following: of the d^(4) species Cr^(2+) is strongly reducing while manganese(III) is strongly oxiding. Cobalt(II) is stable in aqueous solution but in the presence of complexing reagents it is easily oxidised. The D^(1) configuration is very unstable in ions.

Cobalt (II) is stable in aqueous solution but in the presence of complexing reagents ( strong field ligands ) it is readily oxidised. Why ?

How will you account for the following : (i) Cobalt (II) is stable in aqueous solution but in the presence of a complexing agent, it is easily oxidized. (ii) Out of d^(4) species, Cr^(2+) is strongly reducing while Mn^(2+) is strongly oxidising .

(a) How would you account for the following : (i) Cobalt (II) is stable in aqueous solution but in the presence of strong ligands, it is easily oxidised. (ii) The transition metals form interstitial compounds. (iii) Silver halides find use in photography. (b) What is lanthanoid contraction ? Mention its main consequences.

How would you account for the following ? (i) With the same d-orbital configuration (d^(4)) Cr^(2+) is reducting agent while Mn^(3+) is an oxidizing agent. (ii) The actionoids exhibits a larger numbe of oxidation states than the corresponding members in the lanthanoid series. (iii) Most of the transition metal ions exhibit characteristic in colours in aqueous solutions.

Give reasons for the following: (i) Transition metals exhibit a wide range of oxidation states. (ii) Cobalt (II) is very stable in aqueous solutions but gets easily oxidised in the presence of strong ligands. (iii) Actinoids exhibit a greater range of oxidation states than lanthanoids.

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