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Polarisation of electrons in acrolein ma...

Polarisation of electrons in acrolein may be written as :

A

`overset (-delta) CH_2 = CH - overset (+delta)C = O`

B

`overset (-delta) CH_2 = CH - CH = overset (+delta) O`

C

`overset (-delta)CH_2 = overset(+delta)CH - CH = O`

D

`overset (-delta)CH_2 = CH - CH = overset (-delta)O`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `O` atom is more `EN` than `C` atom, so it acquires `(-delta)` charge and `C` atom acquires `(+ delta)` charge which is transferred to the last `C` atom.
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Knowledge Check

  • Polarization of electrons in acrolein may be written as

    A
    `overset(delta-)(CH_(2))=CH-overset(delta+)(CH)=O`
    B
    `overset(delta-)(CH_(2))=CH-CH=overset(delta+)(O)`
    C
    `overset(delta-)(CH_(2))=overset(delta-)(CH)-CH=O`
    D
    `overset(delta+)(CH_(2))=CH-CH=overset(delta-)(O)`

  • Polarization of electrons in acrolein may be written as :

    A
    `overset(-delta)CH_(2)=CH-overset(+delta)C=O`
    B
    `overset(-delta)CH_(2)=CH-CH=overset(+delta)O`
    C
    `overset(-delta)CH_(2)=overset(+delta)CH-CH=O`
    D
    `overset(+delta)CH_(2)=CH-CH=overset(-delta)O`

  • Polarization of electrons in acrolein may be written as:

    A
    `overset(delta^(-))(CH_(2)) = CH-overset(delta^(+))(CH)=O`
    B
    `overset(delta^(+))(CH_(2))=CH-CH=overset(delta^(+))(O)`
    C
    `overset(delta^(-))(CH_(2))=CH-CH=overset(delta^(+))(O)`
    D
    `overset(delta^(+))(CH_(2))=CH-CH=overset(delta^(-))(O)`