a. Write the IUPAC name of the following compounds.

b. Identify `1^(@)` (primary), `2^(@)` (secondery), `3^(@)` (teriary), and `4^(@)` (quaternary) C atoms.
c. Identify all the `1^(@)` , `2^(@)` , `3^(@)` H atoms.

Explanation

a.
Out of 1- and 2-methyl butyl, the first compound has the lower locatant number. So, the numbering of the C chain should start from the side where the locant is at the lowest position of C chain. Hence, the IUPAC name of the compound is 5-(1-methyl butyl)-7-(2-methyl butyl) tridecane.
b. `1^(@)` C is bonded to only one other C. `a=1^(@)`
`2^(@)` C is bonded to two other C atoms. `b=2^(@)`
`3^(@)` C is bonded to three other C atoms. `c=3^(@)`
`4^(@)` C is bonded to four other C atoms. `d=4^(@)`
c. `1^(@)` H atoms are those attached to `1^(@)` C atoms.
`2^(@)` H atoms are those attached to `2^(@)` C atoms.
`3^(@)` H atoms are those attached to `3^(@)` C atoms.
`4^(@)` H atoms do not exist because all four bonds of `4^(@)` C are attached to other C atoms.