Home
Class 11
CHEMISTRY
Explain the formation of products (B), (...

Explain the formation of products (B), (C), and (D) in the following reaction.

Text Solution

Verified by Experts

Two moles of a very strong base, such as butyl lithium `(BuLi)`, convert an alkyne into dianion by the removal of the terminal H and a propargylic H.

Propargylic H is acidic due to resonance stabilisation (extended delocalisation) of the negative charge, as shown:

Moreover, due to the `sp` hybrid character of triple-bonded C, alkyne group `(-C-=C-R)` is EWG (electron withdrawing) and therefore is acid strengthening.
Promotional Banner

Topper's Solved these Questions

  • ALKYNES

    CENGAGE CHEMISTRY|Exercise Solved Examples|24 Videos
  • ALKYNES

    CENGAGE CHEMISTRY|Exercise Exercises (Subjective Type)|31 Videos
  • ALKENES AND ALKADIENES

    CENGAGE CHEMISTRY|Exercise Single correct Answer|14 Videos
  • APPENDIX - INORGANIC VOLUME 1

    CENGAGE CHEMISTRY|Exercise chapter-7 Single correct answer|1 Videos

Similar Questions

Explore conceptually related problems

Explain the formation of (A) and (B) in the following reaction. Oct-1-en eoverset(NBS+C C I_(4))underset(hv)rarrunderset((80%))((A))+underset((20%))((B))

Identify (A),(B),(C ) and (D) in the following reactions :

Product (B) in the following reaction is

Explain the formation of (B), (C ) and (D) in the given reaction:

What are the product A, B, C, D and E in the following reactions?

Identify A, B, C and D in the following reaction sequence