Synthesise the following :
(a) Benzyl alcohol from `G.R`.
(b) 2-Methyl-2-phenyl propanol from `G.R`.
( c) 2-Cyclopropyl ethanol from `G.R`.
(d) `alpha`-Phenyl ethanol from `MeMgl`.
( e) 2-Butanol from acetaldehyde
(f) Triphenyl methanol from benzophenone
(g) `alpha,alpha`-Diphenyl ethanol from acetophenone
(h) 1-Cyclopropyl-1-phenyl ethanol from `PhMgBr`.
(i)

Explanation

(a)
(b)
( c)
(h)
(i) This is an `SN^2` reaction in which the `R` group of the `G.R` acts as a nucleophile, while the `MgBr` coordinated with `O` and gives the product (A). We know that `SN^2` attack leads to the ring opening because the nucleophilic forms a bond with the less substituted `C` atom. Had it been and `SN^1-type` reaction, the nucleophile would have been attached to the more subsituted `C` atom (due to the formation of stable `C^(oplus)` giving the isomer (B) which is it is `SN^1` :