`EtNH_2 + MeMgI overset("Heated at high temp.") underset("in the presence of pyri di ne ")rarr Gas (A)` The volume of gas `(A)` obtained at `S.T.P` when `0.45 gm` of `EtNH_2` reacts with `MeMgI` is.

Options

A. `224 ml`
B. `22.4 ml`
C. `448 ml`
D. 44.8 ml`

Answer

C

Explanation

( c) Only one hydrogen atom in `1^@ RNH_2` reacts at room temperature. In the presence of pyridine, both `H` atoms in `1^@ RNH_2` react.
.
One mole of `EtNH_2` reacts with `2 mol` of `MeMgI` to give `2 mol` of `CH_4 (g)`. Molecular mass of `EtNH_2` is `45 gm`.
Therefore, `45 gm` of `EtNH_2` gives `2 xx 22.4 litres` of `CH_4` at `S.T.P`
`0.45 gm of EtNH_2 gives (2 xx 22.4 xx 0.45)/(45) = 0.448 litres`
=`448 ml`.