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. Hence, CH -= CH overset ((i) 1 mol of ...

. Hence, `CH -= CH overset ((i) 1 mol of (NaNH_2 + liq. NH_3)) underset((ii)A)rarr ( C)`. The product `( C)` is :

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `(B)` is a `1^@` alcohol with three `C` atoms. `HCHO` with `MeMgBr` would give `1^@` alcohol with two `C` atoms. Therefore, `(A)` may be oxirane.
.
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