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Write the mechanism of the reaction of H...

Write the mechanism of the reaction of Hiwith methoxymethane.

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With equimolar amounts of HI and methoxymethane, a mixture of methyl alcohol and methyl iodide is formed by the following mechanism:
Step 1.
Step 2.
If, however, excess of HI is used, methyl alcohol formed in step 2 is also converted into methyl iodide by the following mechanism.
Step 3.
Step 4.
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