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There are two paths for the preparation ...

There are two paths for the preparation of `2-methyl` pentanoic acid `(III)` from `pentan-2-ol (I)`. Which path is feasible and why ?
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Text Solution

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Path `I` is feasible since `II` is a `2^@` halide and with `overset (Ө) C N`. `II` can undergo elimination reaction (dehydrohalo-genation) to give alkene.
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