An amino acid reacts with `10ml 0.05MNaOH` and the final solution has`pH=2.30` When`20ml` of these base is added in the resulting solution.The `pH` become`9.7`.Identify the amino acid and calculate the isoelectric point of the amino acid.This amino acid is prepared by the reaction of compound `(X)`with `NH_(3)`and further hydrolysis with `HCN`compound `(X)` is less `C`atom containing compound that gives postitive iodoform test and positive Fehling's solution test.
Compound (X) is:

Options

A. `CH_(3)CHO`
B. `CH_(3)CH_(2)CHO`
C.
D.

Explanation

Compound (X) is `CH_(3)-overset(O)overset(||)(C)-H`
` (##KSV_CHM_ORG_P2_C15_E01_041_S01.png" width="80%">
When partial neutralisation of alanine occurs .
Then, `pH =pK_(a) +log [("salt")/("acid")]`
`["salt"] = ["acid"]`
`pH_(1) = pK_(a_(1))` and `pH_(2) =pK_(a_(2))`
`:. pH = (pK_(a_(1))+pK_(a_(2)))/(2)=(9.7+2.3)/(2)=(12.0)/(2)=6.0`