For the reaction `O_(3)(g)+O(g)rarr2O_(2)(g)` if the rate law expression is rate =`K[O_(3)][O]` eh molecularity and order of the reaction respectively are

Options

A. 2 and 2
B. 2 and 133
C. 2 and 1
D. 1 and 2

Answer

a

Explanation

Given reaction is `O_(3)(g)+O(g) rarr2O_()(g)` also rate law expression is given as
`rate = k[O_(3))] [O]`
now since molecularity is simply the sum of reactant molecules in a single step of a chemical reaction so molecularity is two for this reaction on the other hand order is the sum of the pwoers raised to the concentration of eractant molecules from eq (i) order is 1+1 =2
`therefore` the molecularity is 2 and order is also 2