In U.C.M., when time interval `delta t to 0` , the angle between change in velocity `(delta v)` and linear velocity ( v) will be

Options

A. `0^(@)`
B. `90^(@)`
C. `180^(@)`
D. `45^(@)`

Answer

B

Explanation

The direction of change in velocity `(deltav)` is given by
`phi = (180^(@) theta)/( 2) = 90^(@) -(theta)/(2)" "…….(i)`
This can be shown garphically as

For small time interval, i.e, `delta t to 0`, then angle between `V_(1)` and `V_(2)` is very small i.e., `theta = 0^(@)`
So , from Eq.(i) , we get
`phi = 90^(@)` .