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A wire of length L and cross-sectional a...

A wire of length L and cross-sectional area A is made of material of Young's modulus Y. The work done in stretching the wire by an amount x is

A

`(Y x^(2) A)/(2L)`

B

`(2Y x^(2)A)/(L)`

C

`(Y x A)/(2L)`

D

`(Y x^(2)A)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

If a force F is applied along the length L of wire for stretching by an amount x, then Young's modulus is given by.
`Y = ("stress")/("strain") = (FL)/(Ax)`
where , A = area of cross -sectional `rArr F =(YA)/(L)x`
The work done in stretching wire is given by
`W = underset(0)overset(x)int F.dx = underset(0)overset(x)int(YA)/(L)x =(YA)/(L)[(x^(2))/(2)]_(0)^(x) =(YAx^(2))/(2L)`
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