The equation of state for 2g of oxygen at a pressure 'P' and temperature 'T , when occupying a volume. 'V will be

Options

A. `pV = 16RT `
B. pV = RT
C. `pV = (1)/(16) RT`
D. pV = 2RT

Answer

C

Explanation

The ideal gas equation is gven by `pV = mu RT " "……(i)`
where `mu` = number of moles in gas
As ` mu =("Given mass")/("Molecular maSss") = (m)/(M)`
and for oxgyen `(O_(2))` M = 32 g
Substituting these value of in Eq.(i) , we get
`pV = (m)/(M)RT = (2)/(32)RT `
`therefore " " pV = (1)/(16)RT`